20v^2-23vb+6b^2=0

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Solution for 20v^2-23vb+6b^2=0 equation: 


Simplifying
20v2 + -23vb + 6b2 = 0

Reorder the terms:
-23bv + 6b2 + 20v2 = 0

Solving
-23bv + 6b2 + 20v2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2b + -5v)(3b + -4v) = 0


Subproblem 1
Set the factor '(2b + -5v)' equal to zero and attempt to solve:

Simplifying
2b + -5v = 0

Solving
2b + -5v = 0

Move all terms containing b to the left, all other terms to the right.

Add '5v' to each side of the equation.
2b + -5v + 5v = 0 + 5v

Combine like terms: -5v + 5v = 0
2b + 0 = 0 + 5v
2b = 0 + 5v
Remove the zero:
2b = 5v

Divide each side by '2'.
b = 2.5v

Simplifying
b = 2.5v

Subproblem 2
Set the factor '(3b + -4v)' equal to zero and attempt to solve:

Simplifying
3b + -4v = 0

Solving
3b + -4v = 0

Move all terms containing b to the left, all other terms to the right.

Add '4v' to each side of the equation.
3b + -4v + 4v = 0 + 4v

Combine like terms: -4v + 4v = 0
3b + 0 = 0 + 4v
3b = 0 + 4v
Remove the zero:
3b = 4v

Divide each side by '3'.
b = 1.333333333v

Simplifying
b = 1.333333333v
Solution
b = {2.5v, 1.333333333v}

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